The difference between two numbers is 16. If one-third of the smaller number is greater than one-seventh of the larger number by 4, then the two numbers are :

Answer: Option C

Let the numbers be x and (x + 16)
Then,
$$\begin{array}{rl}& \iff \frac{x}{3}-\frac{\left(x+16\right)}{7}=4\\ & \iff 7x-3\left(x+16\right)=84\\ & \iff 4x=84+48\\ & \iff 4x=132\\ & \iff x=33\end{array}$$
Hence, the numbers are 33 and 49