The digit in unit's place of the product - ( 2464 )^1793 × ( 615 )^317 × ( 131 )^491

Answer: Option A

$$\begin{array}{rl}& {\left(2464\right)}^{1793}\times {\left(615\right)}^{317}\times {\left(131\right)}^{491}\\ & 4^1\to 4\to 4\\ & 4^2\to 16\to 6\\ & 4^3\to 64\to 4\end{array}$$
So, odd power of 4 will have 4 as unit digit and even power of 4 will have 6 as unit digit 5 and 1 have same unit digits respectively.
(2464)¹⁷⁹³ have the odd power therefore unit digit is 4
(615)³¹⁷ have unit digit 5 and
(131)⁴⁹¹ have unit digit 1.
i.e Unit digit of the product will be 4 × 5 × 1 = 20.
∴ 0 is the unit digit