The distance between two parallel poles is 40√3 m. The angle of depression of the top of the second pole when seen from the top of first pole is 30°. What will be the height of second tower if the first pole is 100 m long

Answer: Option D

Solution

Answer: Option D

Solution:

$$\begin{array}{rl}& \tan 30^{\circ }=\frac{x}{40\sqrt{3}}\\ & \frac{1}{\sqrt{3}}=\frac{x}{40\sqrt{3}}\\ & x=40\\ & \text{So, }y=100-40=60\end{array}$$