The equation for Charle's Law

\frac{V _{2}}{V _{1}} = \frac{T _{2}}{T _{1}} = \frac{273 + C _{2}}{273 + C _{1}} = Constant

Answer

\frac{R A}{R B} = \frac{D B}{D A}

\frac{P _{1} V _{1}}{T _{1}} = \frac{P _{2} V _{2}}{T _{2}} = Constant

\frac{0.4645 B}{273 + t}

Answer: Option A

Answer: Option A

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