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Python · Q53

Exception Handling in Python

Programming · Python · question 53

Q53

The error displayed in the following Python code is? import itertools l1=(1, 2, 3) l2=[4, 5, 6] l=itertools.chain(l1, l2) print(next(l1))

A.
'list' object is not iterator
B.
'tuple' object is not iterator
Answer
C.
'list' object is iterator
D.
'tuple' object is iterator

Answer: Option B

Solution

Answer: Option B
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