The graph of 2x + 1 = 0 and 3y - 9 = 0 intersect at the point?

Answer: Option B

$$\begin{array}{rl}& 2x+1=0\\ & \iff x=\frac{-1}{2}\\ & 3y-9=0\\ & \iff y=\frac{9}{3}=3\\ & \therefore \left(x,y\right)=\left(\frac{-1}{2},3\right)\\ & \text{Point of intersection}\end{array}$$