The graphs of the equations 7x + 11y = 3 and 8x + y = 15 intersect at the point P, which also lies on the graph of the equation:

Answer: Option D

$$\begin{array}{rl}& 7x+11y=3\ast 1\\ & \underline{8x+y=15}\underline{\ast 11}\\ & 7x+11y=3\\ & 88x+11y=165\\ & \underline{---}\\ & -81x=-162\\ & x=2\\ & y=15-8\times 2\\ & y=-1\end{array}$$ Put value of x and y in options only option 'D' satisfy in this values
3x + 5y = 1
3 × 2 + 5 × (-1) = 1
6 - 5 = 1 = 1 [satisfied]