Q45
The Laplace transform of x ( t ) is X ( s ) = e^ - 2s 6s^2 + ss^2 + 2s - 2 The initial value of x ( t ) is
The Laplace transform of is
The initial value of is
The initial value of is
A.
6
B.
2
C.
3
D.
0
AnswerAnswer: Option D
Solution
Answer: Option D
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