The largest 4-digit number exactly divisible by each of 12, 15, 18 and 27 is?

Answer: Option B

LCM of (12, 15, 18, 27)
⇒ 4 × 3 × 5 × 3 × 3 = 540
largest 4-digits number = 9999 on dividing by 540 to number = $$\frac{9999}{540}$$
remainder = 279
Required number = 9999 - 279 = 9720