The least perfect square number divisible by 3, 4, 5, 6 and 8 is = ?

Answer: Option D

L.C.M. of 3, 4, 5, 6, 8 is 120
Now 120 = 2 × 2 × 2 × 3 × 5
To make it a perfect square, it must be multiplied by 2 × 3 × 5
So, required number
$$\begin{array}{rl}& =2^2\times 2^2\times 3^2\times 5^2\\ & =3600\end{array}$$