The matrix form of the linear system dx dt = 3 x - 5 y and dy dt = 4…

Engineering Maths · Q59

Differential Equations

Engineering and GATE · Engineering Maths · question 59

Q59

The matrix form of the linear system

\frac{dx}{dt} = 3 x - 5 y

and

\frac{dy}{dt} = 4 x + 8 y

\frac{{\text{d}}}{{{\text{dt}}}}\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 3&{ - 5} \\ 4&8 \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\}

Answer

\frac{{\text{d}}}{{{\text{dt}}}}\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 3&8 \\ 4&{ - 5} \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\}

\frac{{\text{d}}}{{{\text{dt}}}}\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 4&{ - 5} \\ 3&8 \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\}

\frac{{\text{d}}}{{{\text{dt}}}}\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 4&8 \\ 3&{ - 5} \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} {\text{x}} \\ {\text{y}} \end{array}} \right\}

Answer: Option A

Answer: Option A

No explanation is given for this question Let's Discuss on Board

The matrix form of the linear system dx dt = 3 x - 5 y and dy dt = 4 x + 8 y is