The number nearest to 43582 divisible by each of 25, 50 and 75 is = ?

Answer: Option D

LCM of 25, 50 and 75 = 150
On dividing 43582 by 150, remainder = 82
∴ Required number
= 43582 + (150 – 82)
= 43650

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Alternate
LCM of 25, 50 and 75 = 5 × 5 × 2 × 3 = 150
On dividing 43582 by 150, the remainder is 82 and quotient is 290
So, required number
= 150 × 291
= 43650