The number of candidates passing the examination from City F is what per cent of the total number of candidates appearing from all the cities together? ( rounded off to two digits after the decimal)

Answer: Option A

Total number of candidates from al the 5 cities
= {(1.25 + 3.14 + 1.08 + 2.27 + 1.85 + 2.73) × 100000}
= 12.32 × 100000
= 1232000
Number of candidates passing the exam from city F
$$\begin{array}{rl}& =\frac{7}{12}\times 2.73\times 100000\\ & =\frac{7\times 273\times 1000}{12}\\ & =7\times 91\times 250\\ & =159250\\ & \therefore \text{Required percentage}\\ & =\left(\frac{159250}{1232000}\times 100\right)\%\\ & =\frac{15925}{1232}\%\\ & =12.926\%\\ & \approx 12.93\%\end{array}$$