The number of female athletes who participated from Country E in the year 2009 was approximately what percentage of the total number of athletes who participated from Country B in the year 2008?

Answer: Option B

Number of female athletes from E in 2009
= 9.2 × 100
= 920
Total number of athletes from B in 2008
= (11.4 + 8.4) × 100
= 19.8 × 100
= 1980
Let 920 = x% of 1980
Then,
$$\begin{array}{rl}& \Rightarrow \frac{x}{100}\times 1980=920\\ & \Rightarrow x=\frac{920\times 100}{1980}\\ & =\frac{4600}{99}\%\\ & =46.46\%\\ & \approx 46\%\end{array}$$