The number of integers in between 100 and 600, which are divisible by 4 and 6 both, is :

Answer: Option C

Take L.C.M. of and 6 = 12 and numbers should be divisible by 12.
First number (after 100) = 108
Last of integers
$$\begin{array}{rl}& =\frac{\text{ Last term }-\text{ First term}}{\text{Difference}}+1\\ & =\frac{588-108}{12}+1\\ & =\frac{480}{12}+1\\ & =40+1\\ & =41\end{array}$$