The number of oranges in three basket are in the ratio 3 : 4 : 5. In which ratio the no. of oranges in first two basket must be increased so that the new ratio becomes 5 : 4 : 3 ?

Answer: Option D

Let, B₁ : B₂ : B₃ = 3x : 4x : 5x and
B₁ : B₂ : B₃ = 5y : 4y : 3y
Number of oranges remain constant in third basket as increase in oranges takes place only in first two baskets.
Hence, 5x = 3y
x = $$\frac{3y}{5}$$ and,
∴ 3x : 4x : 5x (putting the vale of x)
= $$\frac{9\text{y}}{5}:\frac{\text{12y}}{5}:\frac{\text{15y}}{5}$$
= 9y : 12y : 15y
And,
5y : 4y : 3y (multiple by 5) → 25y : 20y : 15y
∴Increment in first basket = 16
And, Increment in second basket = 8
Thus, Required ratio = $$\frac{16}{8}$$ = 2 : 1