The remainder obtained when any prime number greater than 6 is divided by 6 must be :

Answer: Option C

Let the required prime number be p.
Let p when divided by 6 give n as quotient and r as remainder. Then p = 6n + r, where 0 $$⩽$$ r < 6
Now, r = 0, r = 2, r = 3 and r = 4 do not give p as prime.
∴ r $$\ne$$ 0, r $$\ne$$ 2, r $$\ne$$ 3, and r $$\ne$$ 4
Hence, r = 1 or r = 5