The remainder of (3)67! divided by 80 is :

Answer: Option B

Since, $$3^4=81$$  gives remainder 1 on divided by 80
So, $$\frac{3^{4n}}{80}$$  gives remainder 1
Thus, $$\frac{3^{67!}}{80}$$  will also give the remainder as 1
Since, 67! = 4n for a positive integer n