The remainder of 6^36215:

Answer: Option B

$$\begin{array}{rl}& \frac{6^{36}}{215},\text{can}\text{be}\text{written}\text{as}\\ & \frac{{\left(6^3\right)}^{12}}{215}\\ & Or,\frac{{216}^{12}}{215},[216\text{on}\text{divided}\text{by}215,\text{gives}\text{remainder}1]\\ & \frac{1^{12}}{215}\\ & \text{The}\text{remainder}\text{will}\text{be}1\end{array}$$