The side BC of a triangle ABC is extended to the point D. If ∠ACD = 132° and ∠B = 4/7 ∠A, then the measure of ∠A is equal to:

Answer: Option D

$$\begin{array}{rl}& \angle \text{B}=\frac{4}{7}\angle \text{A}\\ & \frac{\angle \text{B}}{\angle \text{A}}=\frac{4}{7}\end{array}$$
By exterior angle theorem
7x + 4x = 132°
11x = 132°
x = 12°
∠A = 7 × 12° = 84°