The simplest form of the expression p^2 - p2p^3 + p^2 + p^2 - 1p^2 + 3p + p^2p + 1 = ?

Answer: Option B

$$\frac{p^2-p}{2p^3+p^2}+\frac{p^2-1}{p^2+3p}+\frac{p^2}{p+1}$$
In such type of question assume values of p
$$\begin{array}{rl}& \therefore \text{Let }p=1\\ & \therefore \frac{1-1}{2+1}+\frac{1-1}{1+3}+\frac{1}{1+1}\\ & =0+0+\frac{1}{2}\\ & =\frac{1}{2}\\ & \text{Now check option ’B’}\\ & \frac{1}{2p^2}=\frac{1}{2}\\ & \text{Hence the answer is option ’B’}\end{array}$$