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Aptitude · Q13

Trigonometry

Competitive Exams · Aptitude · question 13

Q13

The simplified value of (secA - cosA)2 + (cosecA - sinA)2 - (cotA - tanA)2

A.
0
B.
C.
1
Answer
D.
2

Answer: Option C

Solution

Answer: Option C
Solution:
(secA - cosA)2 + (cosecA - sinA)2 - (cotA - tanA)2
= (sec2A + cos2A - 2secA.cosA) + (coses2A + sin2A - 2cosecA.sinA) - (cot2A + tan2A - 2cotA.tanA)
= sec2A - tan2A + cos2A + sin2A + coses2A - cot2A - 2
= 3 - 2
= 1

Alternate shortcut method:
(secA - cosA)2 + (cosecA - sinA)2 - (cotA - tanA)2
Put θ = 45°
= (sec45° - cos45°)2 + (cosec45° - sin45°)2 - (cot45° - tan45°)2