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Aptitude · Q83

Problems On H.C.F And L.C.M

Competitive Exams · Aptitude · question 83

Q83

The smallest number, which when increased by 5 is divisible by each of 24, 32, 36 and 64 is ?

A.
869
B.
859
C.
571
Answer
D.
427

Answer: Option C

Solution

Answer: Option C
Solution:
LCM of (24, 32, 36, 64)
⇒ 8 × 3 × 4 × 3 × 2 = 576
Required number is 576 - 5 = 571