Q12
The solution of the differential equation d^2 y d t^2 + 2 dy dt + y = 0 with y(0) = y'(0) = 1 is
The solution of the differential equation with y(0) = y'(0) = 1 is
A.
(2 - t)et
B.
(1 + 2t)e-t
AnswerC.
(2 + t)e-t
D.
(1 - 2t)et
Answer: Option B
Solution
Answer: Option B
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