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Physics GK · Q5

Law of Motion

Competitive Exams · Physics GK · question 5

Q5

The speed of an ant is 75 cm/sec. The ant travels in a day is

A.
64800 m/day
Answer
B.
648000 m/day
C.
648000 cm/day
D.
64800000 cm/day

Answer: Option A

Solution

Answer: Option A
Solution:
1. To find the distance traveled by the ant in one day, we need to convert its speed from cm/sec to m/day.

2. The given speed of the ant is 75 cm/sec. To find the distance traveled in one day, we need to calculate how many seconds are in a day.

3. There are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute, so:

24 × 60 × 60 = 86400 seconds in a day.

4. Now, we can calculate the distance traveled in a day by multiplying the speed by the total number of seconds in a day:

75 cm/sec × 86400 sec/day = 6480000 cm/day.

5. To convert the distance from cm to m, we divide by 100 (since 1 m = 100 cm):

6480000 cm/day ÷ 100 = 64800 m/day.

6. Therefore, the correct answer is Option A: 64800 m/day.