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Aptitude · Q610

Number System

Competitive Exams · Aptitude · question 610

Q610

The sum of the digits of the least number which when divided by 36, 72, 80 and 88 leaves the remainders 16, 52, 60 and 68, respectively, is:

A.
16
Answer
B.
17
C.
11
D.
14

Answer: Option A

Solution

Answer: Option A
Solution:
36 - 16 = 20
72 - 52 = 20
80 - 60 = 20
88 - 68 = 20
LCM of 36, 72, 80, 88 = 7920
Least number = 7920 - 20 = 7900
Sum of the digits = 7 + 9 + 0 + 0 = 16