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Aptitude · Q91

Mensuration 3d

Competitive Exams · Aptitude · question 91

Q91

The sum of the radius of spheres A and B is 14 cm, the radius of A being larger than that of B. The difference between their surface areas is 112π. What is the ratio of the volumes of A and B?

A.
125 : 64
B.
64 : 27
Answer
C.
27 : 8
D.
8 : 1

Answer: Option B

Solution

Answer: Option B
Solution:
Let
Radius of A = R
Radius of B = r
R + r = 14 cm
4π(R2 - r2) = 112π
(R - r)( R + r) = 28
14(R - r) = 28
R - r = 2
R = 8
r = 6
V → R3 : r3 = 43 : 33 = 64 : 27