The sum of third and ninth term of an A.P is 8. Find the sum of the first 11 terms of the progression.

Answer: Option A

The third term t₃ = a + 2d
The ninth term t₉ = a + 8d
t₃ + t₉ = 2a + 10d = 8
Sum of first 11 terms of an AP is given by
$$\begin{array}{rl}& \Rightarrow S_{11}=\frac{11}{2}\left[2a+10d\right]\\ & \Rightarrow S_{11}=\frac{11}{2}\times 8\\ & \Rightarrow S_{11}=44\end{array}$$