Q113
The tangent at a point A of a circle with centre O intersects the diameter PQ of the circle (when extended) at the point B. If ∠BAP = 125°, then ∠AQP is equal to:
A.
50°
B.
55°
AnswerC.
60°
D.
45°
Answer: Option B
Solution
Answer: Option B
Solution:
∵ BAT is a straight line
∠TAP = ∠TAB - ∠BAP
∠TAP = 180° - 125° = 55°
∠AQP = ∠TAP = 55° (by alternate segment theorem)