Q27
The temperature field od a slab is given by T = 400 - 50z exp (-t-x2-y2). The temperature gradient in y-direction is
A.
100yz exp (-t-x2-y2)
AnswerB.
-100yz exp(-t-x2-y2)
C.
100xz exp(-t-x2-y2)
D.
-100xz exp(-t-x2-y2)
Answer: Option A
Solution
Answer: Option A
No explanation is given for this question Let's Discuss on Board