The value of θ(0 ≤ θ ≤ 90°) satisfying 2sin2θ = 3cosθ is?

Answer: Option A

$$\begin{array}{rl}& \text{Hit and Trial method}\\ & \text{Put }\theta =60^{\circ }\text{option A}\\ & \Rightarrow 2{\sin }^{2}60^{\circ }=3\cos 60^{\circ }\\ & \Rightarrow 2{\left(\frac{\sqrt{3}}{2}\right)}^2=3\left(\frac{1}{2}\right)\\ & \Rightarrow \frac{3}{2}=\frac{3}{2}\left(\text{LHS}=\text{RHS}\right)\end{array}$$