The value of 2 ^3 - - 2 ^3 :

Answer: Option C

$$\begin{array}{rl}& \frac{2{\cos }^3\theta -\cos \theta }{\sin \theta -2{\sin }^3\theta }\\ & =\frac{\cos \theta \left[2{\cos }^2\theta -1\right]}{\sin \theta \left[1-2{\sin }^2\theta \right]}\\ & =\frac{\cos \theta \times \cos 2\theta }{\sin \theta \times \cos 2\theta }\\ & =\cot \theta \end{array}$$