The value of 3 7 5 + 2 - 5 5 2 + 7 + 2 2 7 + 5 is:

Answer: Option B

$$\begin{array}{rl}& \frac{3\sqrt{7}}{\sqrt{5}+\sqrt{2}}-\frac{5\sqrt{5}}{\sqrt{2}+\sqrt{7}}+\frac{2\sqrt{2}}{\sqrt{7}+\sqrt{5}}\\ & =\frac{3\sqrt{7}}{\sqrt{5}+\sqrt{2}}\times \frac{\sqrt{5}-\sqrt{2}}{\sqrt{5}-\sqrt{2}}-\frac{5\sqrt{5}}{\sqrt{7}+\sqrt{2}}\times \frac{\sqrt{7}-\sqrt{2}}{\sqrt{7}-\sqrt{2}}+\frac{2\sqrt{2}}{\sqrt{7}+\sqrt{5}}\times \frac{\sqrt{7}-\sqrt{5}}{\sqrt{7}-\sqrt{5}}\\ & =\frac{3\sqrt{7}\left(\sqrt{5}-\sqrt{2}\right)}{{\left(\sqrt{5}\right)}^2-{\left(\sqrt{2}\right)}^2}-\frac{5\sqrt{5}\left(\sqrt{7}-\sqrt{2}\right)}{{\left(\sqrt{7}\right)}^2-{\left(\sqrt{2}\right)}^2}+\frac{2\sqrt{2}\left(\sqrt{7}-\sqrt{5}\right)}{{\left(\sqrt{7}\right)}^2-{\left(\sqrt{5}\right)}^2}\\ & =\sqrt{35}-\sqrt{14}-\sqrt{35}+\sqrt{10}+\sqrt{14}-\sqrt{10}\\ & =0\end{array}$$