The value of 4 ^230^ + ^230^ ^245^ + ^248^ - ^242^ 37^ 53^ + 37^ 53^ + 18^ 72^ \, is:

Answer: Option D

$$\begin{array}{rl}& \frac{4{\tan }^2{30}^{\circ }+{\sin }^2{30}^{\circ }{\cos }^2{45}^{\circ }+{\sec }^2{48}^{\circ }-{\cot }^2{42}^{\circ }}{\cos {37}^{\circ }\sin {53}^{\circ }+\sin {37}^{\circ }\cos {53}^{\circ }+\tan {18}^{\circ }\tan {72}^{\circ }}\\ & =\frac{4{\left(\frac{1}{\sqrt{3}}\right)}^2+{\left(\frac{1}{2}\right)}^2{\left(\frac{1}{\sqrt{2}}\right)}^2+\text{cose}{\text{c}}^2{42}^{\circ }-{\cot }^2{42}^{\circ }}{\cos {37}^{\circ }\cos {37}^{\circ }+\sin {37}^{\circ }\sin {37}^{\circ }+1}\\ & =\frac{4\times \frac{1}{3}+\frac{1}{4}\times \frac{1}{2}+1}{{\cos }^2{37}^{\circ }+{\sin }^2{37}^{\circ }+1}\\ & =\frac{\frac{4}{3}+\frac{1}{8}+1}{1+1}\\ & =\frac{32+3+24}{24\times 2}\\ & =\frac{59}{48}\end{array}$$