The value of 8(sin6θ + cos6θ) - 12(sin4θ + cos4θ) is equal to?

Answer: Option C

$$\begin{array}{rl}& \text{8}\left({\sin }^6\theta +\text{co}{\text{s}}^6\theta \right)-\text{12}\left({\sin }^4\theta +\text{co}{\text{s}}^4\theta \right)\\ & \text{Put }\theta =0^{\circ }\\ & =8\left({\sin }^6{0}^{\circ }+{\cos }^6{0}^{\circ }\right)-12\left({\sin }^4{0}^{\circ }+{\cos }^4{0}^{\circ }\right)\\ & =8\left(0+1\right)-12\left(0+1\right)\\ & =-4\end{array}$$