The value of (ds + t ÷ ds) ÷ dt would be

Answer: Option B

(d^{s + t} ÷ d^s) ÷ d^t
= $$\left(\frac{{\text{d}}^{\text{s}+\text{t}}}{{\text{d}}^{\text{s}}}\right)$$  ÷ d^t
= (d^{s + t - s}) ÷ d^t
= (d^t) ÷ d^t
= $$\frac{{\text{d}}^{\text{t}}}{{\text{d}}^{\text{t}}}$$
= d^{t - t}
= d⁰
= 1