The value of ( 9^2 × 18^43^16 ) is = ?

Answer: Option C

$$\begin{array}{rl}& \left(\frac{9^2\times {18}^4}{3^{16}}\right)\\ & =\frac{9^2\times {\left(9\times 2\right)}^4}{3^{16}}\\ & =\frac{{\left(3^2\right)}^2\times {\left(3^2\right)}^4\times 2^4}{3^{16}}\\ & =\frac{3^4\times 3^8\times 2^4}{3^{16}}\\ & =\frac{3^{\left(4+8\right)}\times 2^4}{3^{16}}\\ & =\frac{3^{12}\times 2^4}{3^{16}}\\ & =\frac{2^4}{3^{\left(16-12\right)}}\\ & =\frac{2^4}{3^4}\\ & =\frac{16}{81}\end{array}$$