The value of sin 65^ 25^ is?

Answer: Option B

$$\begin{array}{rl}& =\frac{\text{sin 6}{5}^{\circ }}{\cos {25}^{\circ }}\\ & =\frac{\text{sin }\left({90}^{\circ }-\text{6}{5}^{\circ }\right)}{\cos {25}^{\circ }}\\ & \left[\sin \left({90}^{\circ }-\theta \right)=\cos \theta \right]\\ & =\frac{\cos {25}^{\circ }}{\cos {25}^{\circ }}\\ & =1\end{array}$$