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Aptitude · Q149

Decimal Fraction

Competitive Exams · Aptitude · question 149

Q149

The value of ( 0.06 )^2 + ( 0.47 )^2 + ( 0.079 )^2 ( 0.006 )^2 + ( 0.047 )^2 + ( 0.0079 )^2 is :

The value of       is :
A.
0.1
B.
10
C.
100
Answer
D.
1000

Answer: Option C

Solution

Answer: Option C
Solution:
Given expression :

Where a = 0.06, b = 0.47 and c = 0.079