The value of se c^217^ - 1 ta n^273^ - 17^ 73^ is?

Answer: Option B

$$\begin{array}{rl}& ={\sec }^{2}17^{\circ }-\frac{1}{{\tan }^2{73}^{\circ }}-\sin 17^{\circ }\sec 73^{\circ }\\ & ={\sec }^{2}17^{\circ }-{\cot }^{2}73^{\circ }-\sin 17^{\circ }\sec \left({90}^{\circ }-{17}^{\circ }\right)\\ & ={\sec }^{2}17^{\circ }-{\cot }^2\left({90}^{\circ }-{17}^{\circ }\right)-\sin 17^{\circ }\cos ec17^{\circ }\\ & ={\sec }^{2}17^{\circ }-{\tan }^{2}17^{\circ }-1\\ & =1-1\left[\because {\sec }^2\theta -{\tan }^2\theta =1\right]\\ & =0\end{array}$$