The value of, sec ( 1 + cos + cos 1 + ) - 2 ta n^2 is?

Answer: Option C

$$\begin{array}{rl}& \text{sec}\theta \left(\frac{1+\sin \theta }{\text{cos}\theta }+\frac{\text{cos}\theta }{1+\sin \theta }\right)-2\text{ta}{\text{n}}^2\theta \\ & \mathbf{Shortcutmethod}:\\ & \text{Take, }\theta =0^{\circ }\\ & \Rightarrow \text{sec }{0}^{\circ }\left(\frac{1+\sin 0^{\circ }}{\text{cos }{0}^{\circ }}+\frac{\text{cos }{0}^{\circ }}{1+\sin 0^{\circ }}\right)-2\text{ta}{\text{n}}^2{0}^{\circ }\\ & \Rightarrow 1\left(\frac{1+0}{1}+\frac{1}{1+0}\right)-0\\ & \Rightarrow 2\end{array}$$