The value of sin230°.cos245° + 2tan230° - sec260° is equal to:

Answer: Option B

$$\begin{array}{rl}& {\sin }^{2}30^{\circ }.{\cos }^{2}45^{\circ }+2{\tan }^{2}30^{\circ }-{\sec }^{2}60^{\circ }\\ & ={\left(\frac{1}{2}\right)}^2.{\left(\frac{1}{\sqrt{2}}\right)}^2+2{\left(\frac{1}{\sqrt{3}}\right)}^2-{\left(2\right)}^2\\ & =\frac{1}{4}\times \frac{1}{2}+2{\left(\frac{1}{\sqrt{3}}\right)}^2-{\left(2\right)}^2\\ & =\frac{1}{8}+\frac{2}{3}-4\\ & =\frac{3+16-96}{24}\\ & =-\frac{77}{24}\end{array}$$