There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

Answer: Option C

Total cases of checking in the hotels = $$4^3$$ ways.
Cases, when 3 men are checking in different hotels = 4 × 3 × 2 = 24 ways.
Required probability:
$$\begin{array}{rl}& =\frac{24}{4^3}\\ & =\frac{3}{8}\end{array}$$