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Aptitude · Q106

Problems On Numbers

Competitive Exams · Aptitude · question 106

Q106

Three times the first of three consecutive odd integers is 3 more than twice the third. The integer is :

A.
9
B.
11
C.
13
D.
15
Answer

Answer: Option D

Solution

Answer: Option D
Solution:
Let the three integers be x, (x + 2) and (x + 4)
Then,
Three times the first of three consecutive odd integers is 3 more than twice the third.
⇔ 3x = 2(x + 4) + 3
⇔ x = 11
∴ Third integer :
= x + 4
= 11 + 4
= 15