ΔABC a right angled triangle has ∠B = 90° and AC is hypotenuse. D is its circumcenter and AB = 3 cms, BC = 4 cms. The value of BD is

Answer: Option C

AC $$=\sqrt{3^2+4^2}=\sqrt{9+16}$$
AC = 5
∵ D is circumcenter, it is equidistant from all the center
So AD = CD = BD = $$\frac{5}{2}$$ = 2.5 cm