ΔABC is isosceles having AB = AC and ∠A = 40°. Bisectors PO and OQ of the exterior angles ∠ABD and ∠ACE formed by producing BC on both sides, meet at O. Then the value of ∠BOC is

Answer: Option A

Solution

Answer: Option A

Solution:

AB = AC
∴ ∠B = ∠C
∠B = $$\frac{{180}^{\circ }-{40}^{\circ }}{2}$$
∠B = 70°
∠B = ∠C = 70°

∠BOC = 90° - $$\frac{\angle \text{A}}{2}$$
= 90° - 20°
= 70°