ΔABC is similar to ΔDEF. If the sides of ΔABC, that is AB, BC and CA, are 3, 4 and 5 cms respectively, what would be the perimeter of the ΔDEF, if the side DE measures 12 cms ?

Answer: Option D

Solution

Answer: Option D

Solution:

Perimeter of ΔABC
= 3 + 4 + 5
= 12
$$\begin{array}{rl}& \frac{\text{Perimeter}\text{of}△ABC}{\text{Perimeter}\text{of}△DEF}=\frac{AB}{DE}\\ & \frac{12}{\text{Perimeter}\text{of}△DEF}=\frac{3}{12}\end{array}$$

Perimeter of ΔDEF = 48 cms