Two cards are drawn from a pack of well shuffled cards. Find the probability that one is a club and other in King.

Answer: Option D

Let X be the event that cards are in a club which is not king and other is the king of club.
Let Y be the event that one is any club card and other is a non-club king.
Hence, required probability:
$$\begin{array}{rl}& =P(A)+P(B)\\ & =\frac{{}^{12}{C}_1{\times }^1{C}_1}{{}^{52}{C}_2}+\frac{{}^{13}{C}_1{\times }^3{C}_1}{{}^{52}{C}_2}\\ & =\left(\frac{2\times \left(12\times 1\right)}{52\times 51}\right)+\left(\frac{2\left(13\times 3\right)}{52\times 51}\right)\\ & =\left(\frac{24+78}{52\times 51}\right)\\ & =\frac{1}{26}\end{array}$$