Two chords of length a unit and b unit of a circle make angles 60° and 90° at the centre of a circle respectively, then the correct relation is:

Answer: Option A

∠AOB = 60°
∠COD = 90°
⇒ length of chord AB = a
⇒ length of chord CD = b
⇒ AO = OB = AB = OD = OC = a
⇒ In ΔODC
⇒ OD² + OC² = CD²
⇒ a² + a² = b²
⇒ b = $$\sqrt{2}$$ a