Two circles C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D and C2 in A, B respectively. If ∠BDC = 120°, then the value of ∠ABP is equal to

Answer: Option A

According to question
Given:

∠BDC = 120°, ∠ABP =?
∴ ∠CDP = 180° - ∠BDC
∠CDP = 180° - 120°
∠CDP = 60°
CD || AB
∴ ∠CDP = ∠ABP = 60°